DATA HANDLING (Statistics) - Q&A
EXERCISE 24
1. Multiple Choice Type:
Choose the correct answer from the options given below.
(i) Lower class limit of 15-18 is:
(a) 15
(b) 18
(c) (18-15)/2
(d) (15+18)/2
Answer: (a) 15
In the class interval 15-18, the smaller number 15 is the lower class limit.
(ii) Upper class limit of 5-12.5 is:
(a) 5
(b) 12.5
(c) (12.5-5)/2
(d) (12.5+5)/2
Answer: (b) 12.5
In the class interval 5-12.5, the larger number 12.5 is the upper class limit.
(iii) If the upper and the lower limits of a class interval are 16 and 10, the class-mark is:
(a) 6
(b) 3
(c) 13
(d) none of these
Answer: (c) 13
Class mark = (Upper limit + Lower limit) / 2 = (16 + 10) / 2 = 26 / 2 = 13.
(iv) If the lower and the upper limits of a class interval are 7.5 and 12.5, the class-mark is:
(a) 10
(b) 2.5
(c) 7.5
(d) 12.5
Answer: (a) 10
Class mark = (7.5 + 12.5) / 2 = 20 / 2 = 10.
(v) In a pie-chart, an angle of 30° represents 80 articles. The number of articles represented by 105° are:
(a) 280
(b) 22 6/7
(c) 200
(d) none of these
Answer: (a) 280
30° represents 80 articles.
1° represents 80/30 articles.
105° represents (80/30) × 105 = 8 × 35 = 280 articles.
(vi) In a pie-chart, 76 articles are represented by 19°, how many articles will be represented by 76°?
(a) 19
(b) 76
(c) 304
(d) none of these
Answer: (c) 304
19° represents 76 articles.
1° represents 76/19 = 4 articles.
76° represents 76 × 4 = 304 articles.
2. Hundred students from a certain locality use different modes of travelling to school as given below. Draw a bar graph.
| Bus | Car | Rickshaw | Bicycle | Walk |
|---|---|---|---|---|
| 32 | 16 | 24 | 20 | 8 |
Answer:
To draw the bar graph:
1. Draw the x-axis (horizontal) and mark the modes of transport: Bus, Car, Rickshaw, Bicycle, Walk.
2. Draw the y-axis (vertical) and mark the scale (e.g., 1 unit = 4 students). Mark values 0, 4, 8, 12, ... up to 36.
3. Draw rectangular bars of equal width for each mode with heights corresponding to the data:
- Bus: Height 32
- Car: Height 16
- Rickshaw: Height 24
- Bicycle: Height 20
- Walk: Height 8
3. Mr. Mirza's monthly income is ₹ 7,200. He spends ₹ 1,800 on rent, ₹ 2,700 on food, ₹ 900 on education of his children, ₹ 1,200 on other things and saves the rest. Draw a pie-chart to represent it.
Answer:
Total Income = ₹ 7,200.
First, find the savings: 7200 - (1800 + 2700 + 900 + 1200) = 7200 - 6600 = ₹ 600.
Calculation of Central Angles:
- Rent: (1800 / 7200) × 360° = (1/4) × 360° = 90°
- Food: (2700 / 7200) × 360° = (3/8) × 360° = 135°
- Education: (900 / 7200) × 360° = (1/8) × 360° = 45°
- Others: (1200 / 7200) × 360° = (1/6) × 360° = 60°
- Savings: (600 / 7200) × 360° = (1/12) × 360° = 30°
(Check: 90+135+45+60+30 = 360°)
Draw a circle and divide it into sectors with these angles.
4. The percentage of marks obtained in different subjects by Ashok Sharma (in an examination) are given below. Draw a bar graph to represent it.
| English | Hindi | Maths | Science | Social Studies |
|---|---|---|---|---|
| 85 | 60 | 35 | 50 | 70 |
Answer:
To draw the bar graph:
1. X-axis: Subjects (English, Hindi, Maths, Science, Social Studies).
2. Y-axis: Marks (Scale: 1 cm = 10 marks). Range 0 to 90.
3. Draw bars with heights:
- English: 85
- Hindi: 60
- Maths: 35
- Science: 50
- Social Studies: 70
5. The following table shows the market position of different brands of tea leaves. Draw a pie-chart to represent the above information.
| Brands | A | B | C | D | others |
|---|---|---|---|---|---|
| % Buyers | 35 | 20 | 20 | 15 | 10 |
Answer:
Total percentage = 100%. Total angle = 360°.
Calculation of Central Angles:
- Brand A: (35 / 100) × 360° = 126°
- Brand B: (20 / 100) × 360° = 72°
- Brand C: (20 / 100) × 360° = 72°
- Brand D: (15 / 100) × 360° = 54°
- Others: (10 / 100) × 360° = 36°
Draw the pie chart using these angles.
6. Students of a small school use different modes of travel to school as shown below : Draw a suitable bar graph.
| Modes | Bus | Car | Bicyle | Auto | On foot |
|---|---|---|---|---|---|
| No. of students | 142 | 98 | 50 | 34 | 16 |
Answer:
To draw the bar graph:
1. X-axis: Modes of travel.
2. Y-axis: No. of students. Scale: 1 unit = 20 students.
3. Heights of bars:
- Bus: 142
- Car: 98
- Bicycle: 50
- Auto: 34
- On foot: 16
7. For the following table, draw a bar-graph.
| A | B | C | D | E | F |
|---|---|---|---|---|---|
| 230 | 400 | 350 | 200 | 380 | 160 |
Answer:
To draw the bar graph:
1. X-axis: Categories (A, B, C, D, E, F).
2. Y-axis: Value. Scale: 1 unit = 50.
3. Heights of bars:
- A: 230
- B: 400
- C: 350
- D: 200
- E: 380
- F: 160
8. Manoj appeared for ICSE examination 2018 and secured percentage of marks as shown in the following table. Represent the above data by drawing a suitable bar graph.
| Subjects | Hindi | English | Maths | Science | Social Study |
|---|---|---|---|---|---|
| Marks as percent | 60 | 45 | 42 | 48 | 75 |
Answer:
To draw the bar graph:
1. X-axis: Subjects.
2. Y-axis: Marks %. Scale: 1 unit = 10%.
3. Heights of bars:
- Hindi: 60
- English: 45
- Maths: 42
- Science: 48
- Social Study: 75
9. For the data given above in question number 8, draw a suitable pie-graph.
Answer:
Sum of the values = 60 + 45 + 42 + 48 + 75 = 270.
Calculation of Central Angles:
- Hindi: (60 / 270) × 360° = 80°
- English: (45 / 270) × 360° = 60°
- Maths: (42 / 270) × 360° = 56°
- Science: (48 / 270) × 360° = 64°
- Social Study: (75 / 270) × 360° = 100°
(Check: 80+60+56+64+100 = 360°)
Draw the pie chart with these sectors.
10. Mr. Kapoor compares the prices (in ₹) of different items at two different shops A and B. Examine the following table carefully and represent the data by a double bar graph.
| Items | Tea-set | Mixer | Coffee-maker | Dinner set |
|---|---|---|---|---|
| Price (in ₹) at shop A | 900 | 700 | 600 | 600 |
| Price (in ₹) at Shop B | 950 | 800 | 700 | 500 |
Answer:
To draw the double bar graph:
1. X-axis: Items (Tea-set, Mixer, Coffee-maker, Dinner set).
2. Y-axis: Price. Scale: 1 unit = ₹ 100.
3. For each item, draw two adjacent bars (one for Shop A, one for Shop B):
- Tea-set: A=900, B=950
- Mixer: A=700, B=800
- Coffee-maker: A=600, B=700
- Dinner set: A=600, B=500
11. The following table shows the modes of transport used by boys and girls for going to the same school. Draw a double bar graph representing the above data.
| Mode | Bus | Bicycle | Walking | Other sources |
|---|---|---|---|---|
| Number of boys | 80 | 60 | 20 | 85 |
| Number of girls | 90 | 75 | 35 | 60 |
Answer:
To draw the double bar graph:
1. X-axis: Modes of transport.
2. Y-axis: Number of students. Scale: 1 unit = 10 students.
3. Draw adjacent bars for Boys and Girls for each mode:
- Bus: Boys=80, Girls=90
- Bicycle: Boys=60, Girls=75
- Walking: Boys=20, Girls=35
- Other sources: Boys=85, Girls=60
Test yourself
1. Multiple Choice Type: Choose the correct answer from the options given below.
(i) The number of times a data, in the set, occurs is called:
(a) upper-limit
(b) class-mark
(c) frequency
(d) class-limit
Answer: (c) frequency
(ii) The difference between the greatest and the smallest values of observations is called:
(a) frequency
(b) range
(c) class-mark
(d) class-limit
Answer: (b) range
(iii) The difference between the upper and lower class-limits of a class-interval is called:
(a) width of the class-interval
(b) frequency
(c) class-limit
(d) class-mark
Answer: (a) width of the class-interval
(iv) In a bar-graph, if the widths of all the bars are kept same, their heights are proportional to their :
(a) class-size
(b) class-mark
(c) class-limits
(d) frequency
Answer: (d) frequency
(v) In a pie-chart, the angle corresponding to different components is:
(a) (value of the component / total value of all the components)
(b) (total value of all the components / value of the component) × 360°
(c) (total value of all the components / 360°)
(d) (value of the component / total value of all the components) × 360°
Answer: (d) (value of the component / total value of all the components) × 360°
(vi) Consider the following class intervals of a grouped data: Class Interval 10-25, 25-40, ..., 55-70.
Statement 1: Class mark of the 3rd class interval is 46.5.
Statement 2: If the class mark of the 2nd class interval is 77.5, the class interval is 60-85.
Which of the following options is correct?
(a) Both the statements are true.
(b) Both the statements are false.
(c) Statement 1 is true, and statement 2 is false.
(d) Statement 1 is false, and statement 2 is true.
Answer: (b) Both the statements are false.
Explanation:
Intervals are 10-25, 25-40, 40-55. 3rd is 40-55. Midpoint = (40+55)/2 = 47.5. Statement 1 says 46.5 (False).
Statement 2: If interval is 60-85, Mark = (60+85)/2 = 72.5. Statement says 77.5 (False).
The following questions are Assertion-Reason based questions. Choose your answer based on the codes given below.
(1) Both A and R are correct, and R is the correct explanation for A.
(2) Both A and R are correct, and R is not the correct explanation for A.
(3) A is true, but R is false.
(4) A is false, but R is true.
(vii) Assertion (A): If in a pie chart representing the number of students opting for different streams in college admission out of a total admission of 3300, the central angle for the sector representing Mathematics is 48° then the number of students who opted for Mathematics is 440.
Reason (R): Central angle for sector (Component) = (Value of the component / Total value) × 360°
(a) (1)
(b) (2)
(c) (3)
(d) (4)
Answer: (a) (1)
Check A: Value = (Angle / 360) × Total = (48/360) × 3300 = 440. A is correct. R is the correct formula.
(viii) Assertion (A): Class size of the following class intervals is 10. 1-10, 11-20, 21-30, etc.
Reason (R): The difference between the upper limit and lower limit is the class size.
(a) (1)
(b) (2)
(c) (3)
(d) (4)
Answer: (c) (3)
A is True (1 to 10 is 10 items). R is False for inclusive series (10-1 = 9, not 10). Class size is (Upper - Lower + 1) or difference of boundaries.
(ix) Assertion (A): The given bar graph shows the heights of six mountain peaks.
Reason (R): The space between consecutive bars may be of any suitable value, but the spaces between all the consecutive bars must the same.
(a) (1)
(b) (2)
(c) (3)
(d) (4)
Answer: (b) (2)
A is True (Graph shows P, Q, R, S, T, V). R is True (Standard rule). R does not explain why the graph shows 6 peaks.
(x) Assertion (A): The distribution of land in Pacific Housing Society is shown in the pie chart below. The total land area for the project is 144000 m². The ratio of the area kept open to the ratio of the area for apartment construction is 5:13.
Reason (R): In a pie chart, the central angle of a sector subtended by its arc is proportional to the value it represents.
(a) (1)
(b) (2)
(c) (3)
(d) (4)
Answer: (d) (4)
R is True. A is likely False because the angles given (90, 36, 234) do not correspond to a 5:13 ratio (100°:260°) for any logical combination of sectors.
2. Draw a bar-graph to represent the following data:
| Articles: | A | B | C | D | E | F | G |
|---|---|---|---|---|---|---|---|
| Price of articles: | 200 | 250 | 150 | 150 | 100 | 50 | 350 |
Answer:
Construct a bar graph:
X-axis: Articles A, B, C, D, E, F, G.
Y-axis: Price. Scale: 1 unit = 50.
Heights: A=200, B=250, C=150, D=150, E=100, F=50, G=350.
3. Study the given graph and then answer the following questions:
(i) Which classes have the larger number of students ?
(ii) Which class has the equal number of girls and boys ?
(iii) What is the total number of students in class VIII ?
(iv) What is the total number of students (from the class VI to class X) ?
Answer:
(Based on the graph where Boys are left bar, Girls are right bar):
(i) Class VI (Approx 110 students) and VII (Approx 110 students).
(ii) Class VIII (Both bars appear at height 30).
(iii) 30 + 30 = 60 students.
(iv) Total = VI(60+50) + VII(50+60) + VIII(30+30) + IX(40+40) + X(20+30) = 110 + 110 + 60 + 80 + 50 = 410 students.
4. The following table shows the number of students in various classes:
| Class | VI | VII | VIII | IX | X |
|---|---|---|---|---|---|
| No. of students | 360 | 300 | 54 | 150 | 216 |
Draw a pie-graph to represent the above data.
Answer:
Total students = 360 + 300 + 54 + 150 + 216 = 1080.
Calculation of Central Angles:
- VI: (360 / 1080) × 360° = 120°
- VII: (300 / 1080) × 360° = 100°
- VIII: (54 / 1080) × 360° = 18°
- IX: (150 / 1080) × 360° = 50°
- X: (216 / 1080) × 360° = 72°
(Check: 120+100+18+50+72 = 360°)
Draw the pie graph with these angles.
5. The given pie-graph represents the number of students in different classes. If the total of all the students in the class is 1080; use the graph to find the number of students in each class.
(Angles: VI=80°, VII=90°, VIII=70°, IX=65°, X=55°)
Answer:
Total students = 1080.
- Class VI: (80 / 360) × 1080 = 80 × 3 = 240 students.
- Class VII: (90 / 360) × 1080 = 90 × 3 = 270 students.
- Class VIII: (70 / 360) × 1080 = 70 × 3 = 210 students.
- Class IX: (65 / 360) × 1080 = 65 × 3 = 195 students.
- Class X: (55 / 360) × 1080 = 55 × 3 = 165 students.