HERON'S FORMULA - Q&A
Exercise 10.1
1. A traffic signal board, indicating 'SCHOOL AHEAD', is an equilateral triangle with side 'a'. Find the area of the signal board, using Heron's formula. If its perimeter is 180 cm, what will be the area of the signal board?
Step 1: Find the area of the equilateral triangle with side 'a' using Heron's formula.
Let the sides of the triangle be a, a, and a.
Semi-perimeter (s) = (a + a + a) / 2 = 3a/2.
Using Heron's formula, Area = √[s(s - a)(s - b)(s - c)]
Here, a = b = c = a.
Area = √[3a/2 (3a/2 - a) (3a/2 - a) (3a/2 - a)]
Area = √[3a/2 (a/2) (a/2) (a/2)]
Area = √[3a4 / 16]
Area = (√3 / 4) a2.
Step 2: Find the area when perimeter is 180 cm.
Perimeter = 180 cm.
Since it is an equilateral triangle, 3a = 180 cm.
Side a = 180 / 3 = 60 cm.
Substitute a = 60 in the area formula:
Area = (√3 / 4) (60)2
Area = (√3 / 4) × 3600
Area = 900√3 cm2.
2. The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig. 10.6). The advertisements yield an earning of ₹ 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?
Step 1: Find the area of one triangular wall.
The sides are a = 122 m, b = 22 m, c = 120 m.
Semi-perimeter s = (122 + 22 + 120) / 2 = 264 / 2 = 132 m.
Using Heron's Formula:
Area = √[s(s - a)(s - b)(s - c)]
Area = √[132 (132 - 122) (132 - 22) (132 - 120)]
Area = √[132 × 10 × 110 × 12]
Area = √[(11 × 12) × 10 × (11 × 10) × 12]
Area = √[11 × 11 × 12 × 12 × 10 × 10]
Area = 11 × 12 × 10
Area = 1320 m2.
Step 2: Calculate the rent.
Rate = ₹ 5000 per m2 per year.
Rent for 1 year (12 months) for 1 m2 = ₹ 5000.
Rent for 3 months for 1 m2 = (5000 × 3) / 12 = ₹ 1250.
Total rent for 1320 m2 for 3 months:
Total Rent = 1320 × 1250
Total Rent = ₹ 16,50,000.
3. There is a slide in a park. One of its side walls has been painted in some colour with a message "KEEP THE PARK GREEN AND CLEAN" (see Fig. 10.7). If the sides of the wall are 15 m, 11 m and 6 m, find the area painted in colour.
Step 1: Identify the sides of the triangle.
a = 15 m, b = 11 m, c = 6 m.
Step 2: Calculate semi-perimeter (s).
s = (15 + 11 + 6) / 2 = 32 / 2 = 16 m.
Step 3: Calculate the area using Heron's Formula.
Area = √[s(s - a)(s - b)(s - c)]
Area = √[16 (16 - 15) (16 - 11) (16 - 6)]
Area = √[16 × 1 × 5 × 10]
Area = √[16 × 50]
Area = √[16 × 25 × 2]
Area = 4 × 5 × √2
Area = 20√2 m2.
Answer: The area painted in colour is 20√2 m2.
4. Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.
Step 1: Find the third side (c).
Perimeter = a + b + c
42 = 18 + 10 + c
42 = 28 + c
c = 42 - 28 = 14 cm.
Step 2: Calculate semi-perimeter (s).
s = Perimeter / 2 = 42 / 2 = 21 cm.
Step 3: Calculate area.
Area = √[s(s - a)(s - b)(s - c)]
Area = √[21 (21 - 18) (21 - 10) (21 - 14)]
Area = √[21 × 3 × 11 × 7]
Area = √[(3 × 7) × 3 × 11 × 7]
Area = √[3 × 3 × 7 × 7 × 11]
Area = 3 × 7 × √11
Area = 21√11 cm2.
5. Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540cm. Find its area.
Step 1: Find the actual lengths of the sides.
Let the sides be 12x, 17x, and 25x.
Perimeter = 12x + 17x + 25x = 540
54x = 540
x = 10.
So, the sides are:
a = 12 × 10 = 120 cm
b = 17 × 10 = 170 cm
c = 25 × 10 = 250 cm
Step 2: Calculate semi-perimeter (s).
s = 540 / 2 = 270 cm.
Step 3: Calculate area.
Area = √[s(s - a)(s - b)(s - c)]
Area = √[270 (270 - 120) (270 - 170) (270 - 250)]
Area = √[270 × 150 × 100 × 20]
Area = √[27 × 10 × 15 × 10 × 100 × 2 × 10]
Area = √[(9 × 3) × (3 × 5) × (2) × 100000]
Area = √[9 × 9 × 100 × 100 × 100]
Let's simplify differently:
Area = √[270 × 150 × 100 × 20]
Area = √[81,000,000]
Area = 9000 cm2.
6. An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
Step 1: Find the third side.
Let equal sides a = 12 cm, b = 12 cm. Let third side be c.
Perimeter = a + b + c = 30
12 + 12 + c = 30
24 + c = 30
c = 6 cm.
Step 2: Calculate semi-perimeter (s).
s = 30 / 2 = 15 cm.
Step 3: Calculate area.
Area = √[s(s - a)(s - b)(s - c)]
Area = √[15 (15 - 12) (15 - 12) (15 - 6)]
Area = √[15 × 3 × 3 × 9]
Area = √[15 × 9 × 9]
Area = 9√15 cm2.
Answer: The area of the triangle is 9√15 cm2.