Light - Reflection and Refraction - Q&A
1. Which one of the following materials cannot be used to make a lens?
(a) Water
(b) Glass
(c) Plastic
(d) Clay
Answer: (d) Clay
Explanation: A lens must be made of a transparent material so that light can pass through it (refraction). Water, glass, and plastic are transparent, but clay is opaque. Therefore, light cannot pass through clay, and it cannot be used to make a lens.
2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus.
Answer: (d) Between the pole of the mirror and its principal focus.
Explanation: A concave mirror forms a real and inverted image for all positions of the object except when the object is placed very close to it (between the Pole 'P' and Focus 'F'). Only in this case, the image formed is virtual, erect, and magnified.
3. Where should an object be placed in front of a convex lens to get a real image of the size of the object?
(a) At the principal focus of the lens
(b) At twice the focal length
(c) At infinity
(d) Between the optical centre of the lens and its principal focus.
Answer: (b) At twice the focal length
Explanation: For a convex lens, if the object is placed at 2F (twice the focal length), the image is also formed at 2F on the other side. This image is real, inverted, and of the same size as the object.
4. A spherical mirror and a thin spherical lens have each a focal length of –15 cm. The mirror and the lens are likely to be
(a) both concave.
(b) both convex.
(c) the mirror is concave and the lens is convex.
(d) the mirror is convex and the lens is concave.
Answer: (a) both concave.
Explanation: According to the sign convention:
- Focal length of a concave mirror is negative (-).
- Focal length of a concave lens is negative (-).
- Focal length of a convex mirror/lens is positive (+).
Since the given focal length is -15 cm, both must be concave.
5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
(a) only plane.
(b) only concave.
(c) only convex.
(d) either plane or convex.
Answer: (d) either plane or convex.
Explanation:
- A plane mirror always forms an erect image (same size).
- A convex mirror also always forms an erect image (smaller size), no matter where the object is.
- A concave mirror forms an inverted image for most positions (except when very close).
6. Which of the following lenses would you prefer to use while reading small letters found in a dictionary?
(a) A convex lens of focal length 50 cm.
(b) A concave lens of focal length 50 cm.
(c) A convex lens of focal length 5 cm.
(d) A concave lens of focal length 5 cm.
Answer: (c) A convex lens of focal length 5 cm.
Explanation:
1. To read small letters, we need a magnifying glass, which is a convex lens.
2. The magnifying power of a lens is inversely proportional to its focal length (Power P = 1/f). This means a lens with a smaller focal length has higher power (more magnification).
Therefore, a convex lens with a smaller focal length (5 cm) is better than one with 50 cm.
7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.
Answer:
Range of object distance: The object must be placed between the Pole (P) and the Focus (F). Since the focal length is 15 cm, the object distance should be less than 15 cm (0 cm to <15 cm).
Nature of the image: Virtual and Erect.
Size of the image: Larger than the object (Magnified).
8. Name the type of mirror used in the following situations.
(a) Headlights of a car.
(b) Side/rear-view mirror of a vehicle.
(c) Solar furnace.
Support your answer with reason.
Answer:
(a) Headlights of a car: Concave Mirror.
Reason: The light bulb is placed at the focus of the concave mirror. This allows the light rays to reflect and emerge as a powerful, parallel beam of light that travels a long distance.
(b) Side/rear-view mirror: Convex Mirror.
Reason: Convex mirrors always form an erect (upright) image. They also have a wider field of view because they are curved outwards, allowing the driver to see a much larger area behind the car.
(c) Solar furnace: Concave Mirror.
Reason: Large concave mirrors are used to concentrate sunlight coming from infinity (parallel rays) onto a single point (the focus). This concentration produces a huge amount of heat at the focus.
9. One-half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.
Answer: Yes, the lens will produce a complete image of the object.
Explanation: Each part of a lens can form the full image. However, since half the lens is covered, fewer light rays will pass through it to form the image. As a result, the brightness (intensity) of the image will be reduced (it will look dimmer), but the full structure of the object will still be visible.
10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
Answer:
Given:
Object height (h) = +5 cm
Object distance (u) = -25 cm (always negative)
Focal length (f) = +10 cm (convex/converging lens is positive)
1. Finding Image Position (v):
Using Lens Formula: 1/f = 1/v - 1/u
1/10 = 1/v - 1/(-25)
1/10 = 1/v + 1/25
1/v = 1/10 - 1/25
1/v = (5 - 2) / 50
1/v = 3 / 50
v = 50 / 3 = +16.67 cm
The image is formed at 16.67 cm on the other side of the lens.
2. Finding Image Size (h'):
Magnification (m) = h'/h = v/u
h'/5 = 16.67 / -25
h' = (16.67 * 5) / -25
h' = -3.33 cm
Nature: Real (since v is positive) and Inverted (since h' is negative).
Size: Diminished (3.33 cm height compared to 5 cm object).
11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.
Answer:
Given:
Focal length (f) = -15 cm (concave lens is always negative)
Image distance (v) = -10 cm (concave lens always forms virtual image on same side)
Finding Object Distance (u):
Lens Formula: 1/f = 1/v - 1/u
1/(-15) = 1/(-10) - 1/u
1/u = 1/(-10) - 1/(-15)
1/u = -1/10 + 1/15
1/u = (-3 + 2) / 30
1/u = -1 / 30
u = -30 cm
The object is placed 30 cm from the lens.
12. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.
Answer:
Given:
Object distance (u) = -10 cm
Focal length (f) = +15 cm (convex mirror is positive)
Finding Image Position (v):
Mirror Formula: 1/f = 1/v + 1/u
1/15 = 1/v + 1/(-10)
1/v = 1/15 + 1/10
1/v = (2 + 3) / 30
1/v = 5 / 30
v = 30 / 5 = +6 cm
Nature: Since 'v' is positive, the image is formed behind the mirror. It is Virtual and Erect.
13. The magnification produced by a plane mirror is +1. What does this mean?
Answer:
1. Magnitude 1: It means the size of the image is exactly the same as the size of the object.
2. Plus sign (+): It means the image is virtual and erect (upright).
14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.
Answer:
Given:
Height (h) = 5 cm
Object distance (u) = -20 cm
Radius (R) = +30 cm → Focal length (f) = R/2 = +15 cm
1. Image Position (v):
Mirror Formula: 1/v + 1/u = 1/f
1/v - 1/20 = 1/15
1/v = 1/15 + 1/20
1/v = (4 + 3) / 60
v = 60 / 7 = +8.57 cm (Behind the mirror)
2. Image Size (h'):
m = h'/h = -v/u
h'/5 = -(8.57) / (-20)
h' = (8.57 * 5) / 20
h' = +2.14 cm
Nature: Virtual, Erect, and Diminished.
15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed, so that a sharp focussed image can be obtained? Find the size and the nature of the image.
Answer:
Given:
Object size (h) = +7 cm
Object distance (u) = -27 cm
Focal length (f) = -18 cm (concave mirror)
1. Screen Position (v):
1/v + 1/u = 1/f
1/v - 1/27 = -1/18
1/v = -1/18 + 1/27
1/v = (-3 + 2) / 54
1/v = -1 / 54
v = -54 cm
The screen should be placed 54 cm in front of the mirror.
2. Image Size (h'):
m = h'/h = -v/u
h'/7 = -(-54) / (-27)
h'/7 = -2
h' = -14 cm
Nature: Real (since can be put on screen), Inverted (negative height), and Magnified (14 cm > 7 cm).
16. Find the focal length of a lens of power - 2.0 D. What type of lens is this?
Answer:
Formula: Power (P) = 1 / f (in metres)
-2.0 = 1 / f
f = 1 / -2.0
f = -0.5 metres (or -50 cm)
Since the focal length (and power) is negative, it is a Concave Lens.
17. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
Answer:
Power (P) = +1.5 D
f = 1 / P
f = 1 / 1.5
f = 10 / 15 = 2 / 3 metres
f = +0.67 metres (or +66.7 cm)
Since the power is positive, it is a Converging Lens (Convex Lens).